Three capacitors each of capacitance C and of breakdown voltage V are joined in series. The capacitance and breakdown voltages of the combination will be
- 3C, V3
- C3, 3V
- 3C, 3V
- C3, V3
Answer
(2) C3, 3V
Solution
For capacitors in series:
1Ceq = 1C + 1C + 1C = 3C
Ceq = C3
Identical capacitors in series share the applied voltage equally, so each can take V before breakdown.
Breakdown voltage of the combination = 3V
Answer: (2)