Three concentric spherical shells have radii a, b and c (a < b < c) and have surface charge densities , - and respectively. If VA, VB and VC denote the potentials of the three shells, then, for c = a + b, we have
- VC = VB VA
- VC VB VA
- VC = VB = VA
- VC = VA VB
Answer
(4) VC = VA VB
Solution
Charge on a shell of radius R: q = 4 R2. Potential of a shell is q4 0 r outside it and q4 0 R (constant) inside it.
VA = 0(a - b + c)
VB = 0 ( a2b - b + c )
VC = 0 ( a2 - b2 + c2c )
Putting c = a + b:
VA = 0(2a)
VC = 0 2a2 + 2aba + b = 0(2a)
VB = 0 ( a2b + a )
VC = VA VB
Answer: (4)