Choose the correct circuit which can achieve the bridge balance.
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Answer
(1) [figure]
Solution
Bridge balance (no current through G): PQ = RS
Upper arms: P = 10 , Q = 10 ; lower arms: R = 15 , S = 5 + RD (diode in series).
1010 = 155 + RD
RD = 10
So the bridge balances only if the diode conducts (forward biased) and offers its forward resistance RD = 10 ; a reverse-biased diode (infinite resistance) or a shorted 5 arm can never balance it.
(1) Long plate (+) on the left: current enters at the left junction and leaves at D; the diode points towards D forward biased balance possible.
(2) Diode points away from D reverse biased.
(3) Diode across the 5 resistor S cannot reach 15 .
(4) Cell reversed diode reverse biased.
Answer: (1)