If t 0 ( 01(3x+5)t dx ) 1t= 5e ( 85 ) 23, then is equal to .
Answer
64
Solution
1 form: limit =eg'(0), where g(t)= 01(3x+5)tdx, g(0)=1
g'(0)= 01 (3x+5)dx= 13 [u u-u ]58= 8 8-5 5-33
Limit =e-1 88/3 5-5/3= 256e 55/3
RHS = 5e 452/3= 4 e 55/3 ⇒ 4 =256
∴ =64
Answer: 64