Treatment of a gas 'X' with a freshly prepared ferrous sulphate solution gives a compound 'Y' as a brown ring. The compounds X and Y are:
- NO and [Fe(NO)]SO4
- NO2 and [Fe(NO2)]SO4
- N2O and [Fe(N2O)]SO4
- N2O4 and [Fe(N2O4)]SO4
Answer
(1) NO and [Fe(NO)]SO4
Solution
Brown ring test (nitrate ion): NO3- is reduced by Fe2+ in conc. H2SO4 to nitric oxide:
NO3- + 3Fe2+ + 4H+ NO + 3Fe3+ + 2H2O
NO combines with excess Fe2+ to form the brown complex:
[Fe(H2O)6]2+ + NO [Fe(H2O)5(NO)]2+ + H2O
i.e. nitrosoferrous sulphate, written [Fe(NO)]SO4
∴ X = NO, Y = [Fe(NO)]SO4
Answer: (1)