When one CO2 molecule is fixed as one molecule of triose phosphate, which of the following photochemically made, high energy chemical intermediates are used in the reduction phase?
- 2 ATP + 2 NADPH
- 1 ATP + 1 NADPH
- 1 ATP + 2 NADPH
- 2 ATP + 1 NADPH
Answer
(1) 2 ATP + 2 NADPH
Solution
Carboxylation: RuBP + CO2 2 PGA
Reduction: each PGA → triose phosphate uses 1 ATP + 1 NADPH
⇒ for the 2 PGA formed from one CO2: 2 ATP + 2 NADPH
Regeneration of RuBP uses 1 more ATP, so as per NCERT the fixation of one CO2 needs 3 ATP and 2 NADPH in all; of these, 2 ATP + 2 NADPH are used in the reduction phase.
Answer: (1)