The hydration energies of K+ and Cl- are -x and -y kJ/mol respectively. If the lattice energy of KCl is -z kJ/mol, then the heat of solution of KCl is :
- x + y + z
- z - (x + y)
- -z - (x + y)
- x - y - z
Answer
(2) z - (x + y)
Solution
Lattice energy given for K+(g) + Cl-(g) KCl(s) is -z; so breaking the lattice needs +z:
KCl(s) K+(g) + Cl-(g); H1 = +z
Hydration: K+(g) + Cl-(g) aq K+(aq) + Cl-(aq); H2 = -x - y
By Hess's law,
solH = H1 + H2
= z - x - y = z - (x + y)
Answer: (2)