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Differential Equations

JEE Main 2024 (Online) 4th April Evening ShiftMCQEasy📈 Topic in 67% papers+4−1
Ques. 1JEE Main 2024, 4 April (Evening Shift)

Let y = y(x) be the solution of the differential equation (x2 + 4)2dy + (2x3y + 8xy - 2)dx = 0. If y(0) = 0, then y(2) is equal to

  1. 2
  2. 8
  3. 16
  4. 32

Answer

(4) 32

Solution

2x3y + 8xy = 2xy(x2 + 4) ⇒ dydx + 2xx2 + 4y = 2(x2 + 4)2 (linear)

2xx2 + 4 dx = e(x2 + 4) ⇒ I.F. = e e(x2 + 4) = x2 + 4

y(x2 + 4) = 2x2 + 4dx = -1 x2 + c

y(0) = 0 c = 0

x = 2: 8y = -11 = 4 y(2) = 32

Answer: (4)

Keep practising — Differential Equations

Ques. 2JEE Main 2024, 4 April (Evening Shift)

Let y = y(x) be the solution of the differential equation (x + y + 2)2 dx = dy, y(0) = -2. Let the maximum and minimum values of the function y = y(x) in [0, 3 ] be and , respectively. If (3 + )2 + 2 = + 3, , Z, then + equals .

Ques. 3JEE Main 2024, 1 February (Morning Shift)

Let y=y(x) be the solution of the differential equation dydx=2x(x+y)3-x(x+y)-1, y(0)=1. Then, ( 1 2+y ( 1 2 ) )2 equals :

  1. 44+ e
  2. 33- e
  3. 21+ e
  4. 12- e
Ques. 4JEE Main 2024, 1 February (Morning Shift)

If x=x(t) is the solution of the differential equation (t+1)dx= (2x+(t+1)4 )dt, x(0)=2, then, x(1) equals .

Ques. 5JEE Main 2024, 1 February (Evening Shift)

Let be a non-zero real number. Suppose f: R R is a differentiable function such that f(0)=2 and x - f(x)=1. If f (x)= f(x)+3, for all x R, then f (- e 2 ) is equal to :

  1. 7
  2. 9
  3. 3
  4. 5
Ques. 6JEE Main 2024, 1 February (Evening Shift)

If dxdy= 1+x-y2y,x(1)=1, then 5x(2) is equal to .

Ques. 7JEE Main 2024, 31 January (Morning Shift)

Let y=y(x) be the solution of the differential equation dydx= ( x)+y x( x- x x), x (0, 2 ) satisfying the condition y ( 4 )=2. Then, y ( 3 ) is

  1. 3 (2+ e 3 )
  2. 3 (1+2 e 3 )
  3. 3 (2+ e 3 )
  4. 32 (2+ e 3 )
Ques. 8JEE Main 2024, 31 January (Morning Shift)

The solution curve of the differential equation y dxdy=x ( e x- e y+1 ), x>0, y>0 passing through the point (e, 1) is

  1. | e yx |=y2
  2. | e yx |=x
  3. | e xy |=y
  4. 2 | e xy |=y+1
Ques. 9JEE Main 2024, 31 January (Evening Shift)

The temperature T(t) of a body at time t=0 is 160 F and it decreases continuously as per the differential equation dTdt=-K(T-80), where K is a positive constant. If T(15)=120 F, then T(45) is equal to

  1. 90 F
  2. 85 F
  3. 80 F
  4. 95 F
Ques. 10JEE Main 2024, 31 January (Evening Shift)

Let y=y(x) be the solution of the differential equation 2x dx+ (e2y 2x+ x )dy=0, 0<x< 2, y( /4)=0. If y( /6)= , then e8 is equal to .

Ques. 11JEE Main 2024, 30 January (Morning Shift)

Let y=y(x) be the solution of the differential equation x dy+\2(1-x) x+x(2-x)\dx=0 such that y(0)=2. Then y(2) is equal to:

  1. 2\ (2)+1\
  2. 2
  3. 1
  4. 2\1- (2)\

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