Given that the equilibrium constant for the reaction, 2SO2(g) + O2(g) 2SO3(g) has a value of 278 at a particular temperature. What is the value of the equilibrium constant for the following reaction at the same temperature ? SO3(g) SO2(g) + 12O2(g)
- 1.8 10-3
- 3.6 10-3
- 6.0 10-2
- 1.3 10-5
Answer
(3) 6.0 10-2
Solution
The second reaction is the first reaction reversed and multiplied by 12.
Reversing a reaction: K 1K; multiplying by 12: K K1/2
⇒ K' = ( 1K )1/2
= 1 278
= 116.67
= 6.0 10-2
Answer: (3)