Given the reaction between 2 gases represented by A2 and B2 to give the compound AB(g), A2(g) + B2(g) 2AB(g) At equilibrium, the concentration of A2 = 3.0 10-3 M, of B2 = 4.2 10-3 M, of AB = 2.8 10-3 M If the reaction takes place in a sealed vessel at 527 , then the value of Kc will be
- 2.0
- 1.9
- 0.62
- 4.5
Answer
(3) 0.62
Solution
For A2(g) + B2(g) 2AB(g):
Kc = [AB]2[A2][B2]
= (2.8 10-3)2(3.0 10-3)(4.2 10-3)
= 7.84 10-612.6 10-6
= 0.62
∵ ng = 2 - 2 = 0, the value does not depend on the volume of the vessel; the temperature only fixes which value of Kc applies.
Answer: (3)