The energy released in the fusion of 2 kg of hydrogen deep in the sun is EH and the energy released in the fission of 2 kg of 235U is EU. The ratio EHEU is approximately: (Consider the fusion reaction as 4 11H + 2e- 24He + 2 + 6 + 26.7 MeV, energy released in the fission reaction of 235U is 200 MeV per fission nucleus and NA = 6.023 1023)
- 7.62
- 25.6
- 9.13
- 15.04
Answer
(1) 7.62
Solution
Fusion: 2 kg of H = 2000 mol, i.e. 2000NA nuclei; every 4 nuclei release 26.7 MeV.
EH = 2000NA4 26.7 MeV
Fission: 2 kg of 235U = 2000235 mol; each nucleus releases 200 MeV.
EU = 2000NA235 200 MeV
EHEU = 26.7 2354 200 7.84, so the closest option is 7.62.
Answer: (1)