One turn of the helix in a B-form DNA is approximately -
- 20 nm
- 3.4 nm
- 2 nm
- 0.34 nm
Answer
(2) 3.4 nm
Solution
As per NCERT, the pitch of the B-DNA helix is 3.4 nm and there are roughly 10 bp in each turn.
⇒ Distance between two consecutive base pairs = 0.34 nm
⇒ One turn = 10 0.34 nm = 3.4 nm
Answer: (2)