A closed organ and an open organ tube are filled by two different gases having same bulk modulus but different densities 1 and 2, respectively. The frequency of 9th harmonic of closed tube is identical with 4th harmonic of open tube. If the length of the closed tube is 10 cm and the density ratio of the gases is 1: 2=1:16, then the length of the open tube is :
- 157 cm
- 209 cm
- 207 cm
- 159 cm
Answer
(2) 209 cm
Solution
Closed pipe f= nv14L1 (n odd); open pipe f= nv22L2; v= B/ .
v2v1= 1 2= 14
9v14L1= 4v22L2 L2= 8L19 v2v1
L2= 809 14= 209 cm
Answer: (2)