PYQSidePowered byPrepblink ExamsMy practice

Equilibrium

JEE Main 2025 (Online) 24th January Morning ShiftNumericalMedium📈 Topic in 21% papers+4
Ques. 1JEE Main 2025, 24 January (Morning Shift)

37.8 g N2O5 was taken in a 1 L reaction vessel and allowed to undergo the following reaction at 500 K 2N2O5(g) 2N2O4(g) + O2(g) The total pressure at equilibrium was found to be 18.65 bar. Then, Kp = 10-2 [nearest integer] Assume N2O5 to behave ideally under these conditions. Given: R = 0.082 bar L mol-1 K-1

Answer

962

Solution

n= 37.8108=0.35 mol p0= nRTV= 0.35 0.082 5001=14.35 bar

[figure]

ptotal=14.35+p=18.65 p=4.3 bar

pN2O5=5.75, pN2O4=8.6, pO2=4.3 bar

Kp= (8.6)2(4.3)(5.75)2=9.62 bar =962 10-2

Answer: 962

Keep practising — Equilibrium

Ques. 2JEE Main 2025, 24 January (Evening Shift)

For the reaction, H2(g)+I2(g) 2HI(g) Attainment of equilibrium is predicted correctly by :

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 3JEE Main 2025, 23 January (Morning Shift)

Which of the following happens when NH4OH is added gradually to the solution containing 1 M A2+ and 1M B3+ ions? Given : Ksp [A(OH)2] = 9 10-10 and Ksp [B(OH)3] = 27 10-18 at 298 K.

  1. A(OH)2 will precipitate before B(OH)3
  2. A(OH)2 and B(OH)3 will precipitate together
  3. Both A(OH)2 and B(OH)3 do not show precipitation with NH4OH
  4. B(OH)3 will precipitate before A(OH)2
Ques. 4JEE Main 2025, 23 January (Morning Shift)

If 1 mM solution of ethylamine produces pH=9, then the ionization constant (Kb) of ethylamine is 10-x. The value of x is (nearest integer). [The degree of ionization of ethylamine can be neglected with respect to unity.]

Ques. 5JEE Main 2025, 23 January (Evening Shift)

pH of water is 7 at 25 C. If water is heated to 80 C, it's pH will :

  1. Decrease
  2. Remains the same
  3. Increase
  4. H+ concentration increases, OH- concentration decreases
Ques. 6JEE Main 2025, 23 January (Evening Shift)

Consider the reaction X2Y(g) X2(g) + 12Y2(g) The equation representing correct relationship between the degree of dissociation (x) of X2Y(g) with its equilibrium constant Kp is . Assume x to be very very small.

  1. x = [3] KpP
  2. x = [3] Kp2P
  3. x = [3] 2 Kp2P
  4. x = [3] 2KpP
Ques. 7JEE Main 2025, 22 January (Morning Shift)

A vessel at 1000 K contains CO2 with a pressure of 0.5 atm. Some of CO2 is converted into CO on addition of graphite. If total pressure at equilibrium is 0.8 atm, then Kp is :

  1. 0.18 atm
  2. 0.3 atm
  3. 3 atm
  4. 1.8 atm
Ques. 8JEE Main 2025, 22 January (Evening Shift)

The molar solubility(s) of zirconium phosphate with molecular formula ( Zr4+ )3 ( PO43- )4 is given by relation :

  1. ( Ksp5348 )1/6
  2. ( Ksp8435 )1/7
  3. ( Ksp6912 )1/7
  4. ( Ksp9612 )1/3

All Equilibrium PYQs →

PDFDownload Equilibrium PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Chemistry chapters
Physical ChemistrySome Basic Concepts of ChemistryStructure of AtomStates of MatterThermodynamicsEquilibriumRedox ReactionsSolutionsElectrochemistryChemical Kinetics
Inorganic ChemistryClassification of Elements and Periodicity in PropertiesChemical Bonding and Molecular Structurep-Block Elements (Group 13 & 14)p-Block Elements (Group 15–18)d- and f-Block ElementsCoordination Compounds
Organic ChemistryOrganic Chemistry – Some Basic Principles and TechniquesIsomerismHydrocarbonsHaloalkanes and HaloarenesAlcohols, Phenols and EthersAldehydes, Ketones and Carboxylic AcidsAminesBiomoleculesPrinciples Related to Practical Chemistry