The number of molecules/ion/s having trigonal bipyramidal shape is . PF5, BrF5, PCl5, [PtCl4]2-, BF3, Fe(CO)5
Answer
3
Solution
[figure]
PF5, PCl5: 5 bp, 0 lp (sp3d) ⇒ trigonal bipyramidal
Fe(CO)5: dsp3 ⇒ trigonal bipyramidal
BrF5: 5 bp + 1 lp ⇒ square pyramidal
[PtCl4]2-: dsp2 ⇒ square planar; BF3: sp2 ⇒ trigonal planar
∴ trigonal bipyramidal = 3
Answer: 3