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Application of Derivatives

Previous year questions with solutions · 2025 – 2026

19Questions
19Papers covered
2.53% ↑8.3%Weightage in 2026
’25
’26
Year-wise statistics questions · papers · average per paper · weightage
YearQuestionsPapersAvg / paperWeightage
202612190.632.53% ↑8.3%
20257120.582.33%

16 questions · newest paper first

1

For the function f(x)=e |x|-|x|, x R, consider the following statements : In the light of the above statements, choose the correct answer from the options given below :

  1. Both Statement I and Statement II are true
  2. Both Statement I and Statement II are false
  3. Statement I is true but Statement II is false
  4. Statement I is false but Statement II is true
JEE Main 2026 (Online) 8th April Evening Shift
2

Let A= bmatrix1 & 3 & -1\ 2 & 1 & \ 0 & 1 & -1 bmatrix be a singular matrix. Let f(x)= 0x (t2+2t+3 )dt, x [1, ]. If M and m are respectively the maximum and the minimum values of f in [1, ], then 3(M-m) is equal to :

  1. 64
  2. 68
  3. 72
  4. 76
JEE Main 2026 (Online) 6th April Evening Shift
3

Let f : R R be a differentiable function such that f ( x+y3 )= f(x)+f(y)3 for all x, y R, and f'(0)=3. Then the minimum value of the function g(x)=3+ex f(x), is:

  1. 3 ( e+1e )
  2. 3 ( e-1e )
  3. 3-ee
  4. 3e
JEE Main 2026 (Online) 5th April Morning Shift
4

0 x (16 ( x2 ) 3 ( x2 ) ) is equal to :

  1. 3 32
  2. 3 3
  3. 4 3
  4. 6 3
JEE Main 2026 (Online) 4th April Evening Shift
5

The number of critical points of the function f(x)= cases | xx |, & x 0\ 1, & x=0 cases in the interval (-2 , 2 ) is equal to :

  1. 1
  2. 3
  3. 5
  4. 7
JEE Main 2026 (Online) 2nd April Morning Shift
6

Let f(x) be a polynomial of degree 5, and have extrema at x=1 and x=-1. If x 0 ( f(x)x3 )=-5, then f(2)-f(-2) is equal to:

  1. 0
  2. 50
  3. 92
  4. 112
JEE Main 2026 (Online) 2nd April Evening Shift
7

Consider the following three statements for the function f : (0, ) R defined by f(x) = | e x| - |x - 1| : (I) f is differentiable at all x > 0. (II) f is increasing in (0, 1). (III) f is decreasing in (1, ). Then

  1. Only (I) is TRUE.
  2. Only (I) and (III) are TRUE.
  3. Only (II) and (III) are TRUE.
  4. All (I), (II) and (III) are TRUE.
JEE Main 2026 (Online) 24th January Evening Shift
8

Let f(x) = x2025 - x2000, x [0, 1] and the minimum value of the function f(x) in the interval [0, 1] be (80)80(n)-81. Then n is equal to

  1. -40
  2. -41
  3. -80
  4. -81
JEE Main 2026 (Online) 22nd January Morning Shift
9

Let f : R R be a twice differentiable function such that f''(x) > 0 for all x R and f'(a - 1) = 0, where a is a real number. Let g(x) = f( 2 x - 2 x + a), 0 < x < 2. Consider the following two statements: (I) g is increasing in (0, 4 ) (II) g is decreasing in ( 4, 2 ) Then,

  1. Both (I) and (II) are True
  2. Neither (I) nor (II) is True
  3. Only (I) is True
  4. Only (II) is True
JEE Main 2026 (Online) 21st January Evening Shift
10

Let the function f(x) = x3 + 3x + 3, x 0 be strictly increasing in (- , 1) ( 2, ) and strictly decreasing in ( 3, 4) ( 4, 5). Then i=15 i2 is equal to

  1. 48
  2. 40
  3. 36
  4. 28
JEE Main 2025 (Online) 8th April Evening Shift
11

Let x = -1 and x = 2 be the critical points of the function f(x) = x3 + ax2 + b e |x| + 1, x 0. Let m and M respectively be the absolute minimum and the absolute maximum values of f in the interval [-2, - 12 ]. Then |M + m| is equal to (Take e 2 = 0.7):

  1. 21.1
  2. 19.8
  3. 22.1
  4. 20.9
JEE Main 2025 (Online) 7th April Morning Shift
12

Let f : R R be a polynomial function of degree four having extreme values at x = 4 and x = 5. If x 0 f(x)x2 = 5, then f(2) is equal to :

  1. 8
  2. 10
  3. 12
  4. 14
JEE Main 2025 (Online) 7th April Evening Shift
13

Let a > 0. If the function f(x) = 6x3 - 45ax2 + 108a2x + 1 attains its local maximum and minimum values at the points x1 and x2 respectively such that x1 x2 = 54, then a + x1 + x2 is equal to :

  1. 15
  2. 13
  3. 24
  4. 18
JEE Main 2025 (Online) 4th April Evening Shift
14

Let f : R R be a function defined by f(x) = ||x + 2| - 2|x| |. If m is the number of points of local minima and n is the number of points of local maxima of f, then m + n is

  1. 3
  2. 4
  3. 2
  4. 5
JEE Main 2025 (Online) 3rd April Evening Shift
15

If the function f(x) = 2x3 - 9ax2 + 12a2x + 1, where a > 0, attains its local maximum and local minimum values at p and q, respectively, such that p2 = q, then f(3) is equal to :

  1. 55
  2. 37
  3. 10
  4. 23
JEE Main 2025 (Online) 2nd April Morning Shift
16

The sum of all local minimum values of the function f(x) = cases 1 - 2x, & x < -1 \ 13(7 + 2|x|), & -1 x 2 \ 1118(x - 4)(x - 5), & x > 2 cases is

  1. 16772
  2. 15772
  3. 17172
  4. 13172
JEE Main 2025 (Online) 28th January Morning Shift