The number of hydrogen atoms present in 5.4 g of urea is : (Given : Molar mass of urea : 60 g mol-1, NA : 6.022 × 1023 particles mol-1)
- 2.168 × 1022
- 2.168 × 1023
- 1.084 × 1022
- 1.084 × 1023
Previous year questions with solutions · 2000 – 2026
| Year | Questions | Papers | Avg / paper | Weightage |
|---|---|---|---|---|
| 2026 | 4 | 2 | 2 | 4.44% →0% |
| 2025 | 2 | 1 | 2 | 4.44% ↓10.2% |
| 2024 | 5 | 2 | 2.5 | 4.95% ↑152.5% |
| 2023 | 1 | 1 | 1 | 1.96% ↓34% |
| 2022 | 3 | 2 | 1.5 | 2.97% ↑48.5% |
| 2021 | 1 | 1 | 1 | 2.00% ↓10% |
| 2020 | 1 | 1 | 1 | 2.22% →0% |
| 2019 | 1 | 1 | 1 | 2.22% ↓50% |
| 2018 | 2 | 1 | 2 | 4.44% ↑300% |
| 2016 | 1 | 2 | 0.5 | 1.11% ↓80% |
| 2015 | 5 | 2 | 2.5 | 5.56% ↓16.7% |
| 2014 | 3 | 1 | 3 | 6.67% ↑97.8% |
| 2013 | 3 | 2 | 1.5 | 3.37% ↑173% |
| 2011 | 1 | 2 | 0.5 | 1.23% ↓50.6% |
| 2010 | 2 | 2 | 1 | 2.50% ↑27.5% |
| 2009 | 1 | 1 | 1 | 1.96% ↓75% |
| 2008 | 4 | 1 | 4 | 7.84% ↑96.1% |
| 2007 | 2 | 1 | 2 | 4.00% ↑92% |
| 2004 | 1 | 1 | 1 | 2.08% ↑2.1% |
| 2003 | 1 | 1 | 1 | 2.04% ↓66% |
| 2002 | 3 | 1 | 3 | 6.00% ↑2% |
| 2001 | 3 | 1 | 3 | 5.88% ↑200% |
| 2000 | 1 | 1 | 1 | 1.96% |
⚠ 3 of these questions are out of the current syllabus (marked on the question).
The number of hydrogen atoms present in 5.4 g of urea is : (Given : Molar mass of urea : 60 g mol-1, NA : 6.022 × 1023 particles mol-1)
Among the following, choose the ones with equal number of atoms. Choose the correct answer from the options given below:
The highest number of helium atoms is in
1.0 g of H2 has same number of molecules as in:
Which one of the following has maximum number of atoms?
In which case is number of molecules of water maximum?
Suppose the elements X and Y combine to form two compounds XY2 and X3Y2. When 0.1 mole of XY2 weighs 10 g and 0.05 mole of X3Y2 weighs 9 g, the atomic weights of X and Y are
If Avogadro number NA, is changed from 6.022 1023 mol-1 to 6.022 1020 mol-1, this would change
The number of water molecules is maximum in
A mixture of gases contains H2 and O2 gases in the ratio of 1 : 4 (w/w). What is the molar ratio of the two gases in the mixture ?
Which has the maximum number of molecules among the following ?
The number of atoms in 0.1 mol of a triatomic gas is ( NA = 6.02 1023 mol-1)
Volume occupied by one molecule of water (density = 1 g cm-3) is
The maximum number of molecules is present in
Which has maximum molecules?
Specific volume of cylindrical virus particle is 6.02 10-2 cc/g whose radius and length are 7 A and 10 A respectively. If NA = 6.02 1023, find molecular weight of virus.