Which one of the following has maximum number of atoms?
- 1 g of Mg(s) [Atomic mass of Mg = 24]
- 1 g of O2(g) [Atomic mass of O = 16]
- 1 g of Li(s) [Atomic mass of Li = 7]
- 1 g of Ag(s) [Atomic mass of Ag = 108]
Answer
(3) 1 g of Li(s) [Atomic mass of Li = 7]
Solution
Number of atoms = (moles of atoms) × NA, so compare the moles of atoms.
1 g Mg: 124 mol atoms
1 g O2: 132 mol molecules ⇒ 232 = 116 mol atoms
1 g Li: 17 mol atoms
1 g Ag: 1108 mol atoms
∴ 17 is the largest ⇒ 1 g of Li contains the maximum number of atoms ( 17NA ).
Answer: (3)