Volume occupied by one molecule of water (density = 1 g cm-3) is
- 3.0 10-23 cm3
- 5.5 10-23 cm3
- 9.0 10-23 cm3
- 6.023 10-23 cm3
Answer
(1) 3.0 10-23 cm3
Solution
Molar mass of H2O = 18 g mol-1
Mass of one molecule = 186.022 1023
= 2.99 10-23 g
Volume = massdensity = 2.99 10-23 g1 g cm-3
3.0 10-23 cm3
Answer: (1)