Match List I with List II Choose the correct answer from the options given below :
- (A)-(IV), (B)-(III), (C)-(I), (D)-(II)
- (A)-(II), (B)-(III), (C)-(I), (D)-(IV)
- (A)-(I), (B)-(IV), (C)-(II), (D)-(III)
- (A)-(II), (B)-(IV), (C)-(I), (D)-(III)
Answer
(4) (A)-(II), (B)-(IV), (C)-(I), (D)-(III)
Solution
= n(n + 2) B.M., where n = number of unpaired electrons.
(A): Cr3+ (3d3) has n = 3, so = 15 = 3.87 and (A) is (II).
(B): Ni2+ (3d8) with weak-field Cl- is tetrahedral with n = 2, so = 8 = 2.83 and (B) is (IV).
(C): Co3+ (3d6) with weak-field F- is high spin with n = 4, so = 24 = 4.90 and (C) is (I).
(D): Ni2+ with strong-field CN- is square planar (dsp2) with n = 0, so = 0 and (D) is (III).
Answer: (4)