PYQSidePowered byPrepblink ExamsMy practice

Coordination Compounds

JEE Main 2024 (Online) 6th April Morning ShiftMCQMedium📈 Topic in 10% papers+4−1
Ques. 1JEE Main 2024, 6 April (Morning Shift)

Consider the following complexes (A) [CoCl(NH3)5]2+, (B) [Co(CN)6]3-, (C) [Co(NH3)5(H2O)]3+, (D) [Cu(H2O)4]2+ The correct order of A, B, C and D in terms of wavenumber of light absorbed is :

  1. D < A < C < B
  2. B < C < A < D
  3. C < D < A < B
  4. A < C < B < D

Answer

(1) D < A < C < B

Solution

= 1 E (crystal field splitting)

A, B, C are all Co(III) ⇒ Δ follows the sixth ligand: Cl- < H2O < CN- ⇒ A < C < B

∵ D is Cu(II) — lower charge, weak H2O ligands, only 4 ligands ⇒ smallest Δ

∴ D < A < C < B

Answer: (1)

Keep practising — Coordination Compounds

Ques. 2JEE Main 2024, 6 April (Evening Shift)

Match List I with List II. Choose the correct answer from the options given below :

  1. A-IV, B-III, C-I, D-II
  2. A-III, B-I, C-IV, D-II
  3. A-I, B-III, C-IV, D-II
  4. A-III, B-IV, C-II, D-I
Ques. 3JEE Main 2024, 6 April (Evening Shift)

The correct IUPAC name of [PtBr2(PMe3)2] is :

  1. bis(trimethylphosphine)dibromoplatinum(II)
  2. dibromodi(trimethylphosphine)platinum(II)
  3. dibromobis(trimethylphosphine)platinum(II)
  4. bis[bromo(trimethylphosphine)]platinum(II)
Ques. 4JEE Main 2024, 5 April (Morning Shift)

The correct order of ligands arranged in increasing field strength.

  1. F- < Br- < I- < NH3
  2. H2O < -OH < CN- < NH3
  3. Br- < F- < H2O < NH3
  4. Cl- < -OH < Br- < CN-
Ques. 5JEE Main 2024, 5 April (Morning Shift)

Which one of the following complexes will exhibit the least paramagnetic behaviour ? [Atomic number, Cr = 24, Mn = 25, Fe = 26, Co = 27]

  1. [Fe(H2O)6]2+
  2. [Mn(H2O)6]2+
  3. [Co(H2O)6]2+
  4. [Cr(H2O)6]2+
Ques. 6JEE Main 2024, 5 April (Evening Shift)

The number of complexes from the following with no electrons in the t2 orbital is . TiCl4, [MnO4]-, [FeO4]2-, [FeCl4]-, [CoCl4]2-

  1. 4
  2. 2
  3. 3
  4. 1
Ques. 7JEE Main 2024, 5 April (Evening Shift)

The metal atom present in the complex MABXL (where A, B, X and L are unidentate ligands and M is metal) involves sp3 hybridization. The number of geometrical isomers exhibited by the complex is :

  1. 0
  2. 2
  3. 3
  4. 4
Ques. 8JEE Main 2024, 4 April (Morning Shift)

Number of complexes from the following with even number of unpaired "d" electrons is [V(H2O)6]3+, [Cr(H2O)6]2+, [Fe(H2O)6]3+, [Ni(H2O)6]3+, [Cu(H2O)6]2+ [Given atomic numbers: V = 23, Cr = 24, Fe = 26, Ni = 28, Cu = 29]

  1. 1
  2. 5
  3. 2
  4. 4
Ques. 9JEE Main 2024, 4 April (Morning Shift)

The correct sequence of ligands in the order of decreasing field strength is :

  1. NCS- > EDTA4- > CN- > CO
  2. CO > H2O > F- > S2-
  3. S2- > -OH > EDTA4- > CO
  4. -OH > F- > NH3 > CN-
Ques. 10JEE Main 2024, 4 April (Evening Shift)

If an iron (III) complex with the formula [Fe(NH3)x(CN)y]- has no electron in its eg orbital, then the value of x + y is

  1. 6
  2. 4
  3. 3
  4. 5
Ques. 11JEE Main 2024, 4 April (Evening Shift)

The number of unpaired d-electrons in [Co(H2O)6]3+ is .

  1. 0
  2. 2
  3. 1
  4. 4

All Coordination Compounds PYQs →

PDFDownload Coordination Compounds PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Chemistry chapters