The metal atom present in the complex MABXL (where A, B, X and L are unidentate ligands and M is metal) involves sp3 hybridization. The number of geometrical isomers exhibited by the complex is :
- 0
- 2
- 3
- 4
Answer
(1) 0
Solution
sp3 ⇒ tetrahedral complex [MABXL]
∵ in a tetrahedron all four positions are adjacent to one another (all angles 109.5°), no cis / trans arrangement is possible
∴ geometrical isomers = 0 (it shows only optical isomerism, being of type Mabcd)
Answer: (1)