The rate of a reaction quadruples when temperature changes from 27 to 57 . Calculate the energy of activation. Given R = 8.314 J K-1 mol-1, 4 = 0.6021
- 38.04 kJ/mol
- 380.4 kJ/mol
- 3.80 kJ/mol
- 3804 kJ/mol
Answer
(1) 38.04 kJ/mol
Solution
T1 = 27 + 273 = 300 K, T2 = 57 + 273 = 330 K, k2k1 = 4
Arrhenius equation: k2k1 = Ea2.303R ( T2 - T1T1T2 )
Ea = 2.303R 4 T1T2T2 - T1
= 2.303 8.314 0.6021 300 33030
= 11.528 3300
= 38044 J mol-1
Ea 38.04 kJ/mol
Answer: (1)