Match List - I with List - II. Choose the correct answer from the options given below :
- (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
- (A)-(IV), (B)-(II), (C)-(III), (D)-(I)
- (A)-(IV), (B)-(II), (C)-(I), (D)-(III)
- (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
Answer
(3) (A)-(IV), (B)-(II), (C)-(I), (D)-(III)
Solution
(A): ester → aldehyde (partial reduction, stops at –CHO) ⇒ DIBAL-H, H2O ⇒ (A) is (IV)
(B): C=O → CH2 (Clemmensen reduction) ⇒ Zn(Hg) and conc. HCl ⇒ (B) is (II)
(C): –CHO + CH3MgBr, then H2O ⇒ 2° alcohol with one extra C ⇒ (C) is (I)
(D): only the keto C=O → CH(OH); ∵ NaBH4 does not reduce the ester ⇒ (D) is (III)
∴ (A)-(IV), (B)-(II), (C)-(I), (D)-(III)
Answer: (3)