Match List-I with List-II : Choose the correct answer from the options given below.
- (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
- (a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)
- (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
- (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)
Answer
(1) (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
Solution
Magnetic moment = n(n+2) BM, n = number of unpaired electrons. CN- is a strong field ligand (pairing occurs); H2O is a weak field ligand.
(a) [Fe(CN)6]3-: Fe3+, 3d5 low spin (t2g5) ⇒ n = 1 ⇒ = 3 = 1.73 BM → (iv)
(b) [Fe(H2O)6]3+: 3d5 high spin (t2g3 eg2) ⇒ n = 5 ⇒ = 35 = 5.92 BM → (i)
(c) [Fe(CN)6]4-: Fe2+, 3d6 low spin (t2g6) ⇒ n = 0 ⇒ = 0 BM → (ii)
(d) [Fe(H2O)6]2+: 3d6 high spin (t2g4 eg2) ⇒ n = 4 ⇒ = 24 = 4.90 BM → (iii)
∴ (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
Answer: (1)