The geometry and magnetic behaviour of the complex [Ni(CO)4] are
- square planar geometry and diamagnetic
- tetrahedral geometry and diamagnetic
- square planar geometry and paramagnetic
- tetrahedral geometry and paramagnetic
Answer
(2) tetrahedral geometry and diamagnetic
Solution
In [Ni(CO)4], Ni is in the zero oxidation state: Ni(0) = [Ar] 3d8 4s2.
CO is a strong field ligand ⇒ the 4s electrons pair up in 3d ⇒ 3d10.
⇒ The empty 4s and three 4p orbitals give sp3 hybridisation.
Tetrahedral geometry, no unpaired electron ⇒ diamagnetic.
Answer: (2)