Let O be the origin, OP= a and OQ= b. If R is the point on OP such that OP=5 OR, and M is the point such that OQ=5 RM, then PM is equal to :
- 15 ( a-4 b )
- 15 ( b-4 a )
- 15 (- a+4 b )
- 15 (- b+4 a )
Answer
(2) 15 ( b-4 a )
Solution
OP=5 OR OR= a5
OQ=5 RM RM= b5
OM= OR+ RM= a+ b5
PM= OM- OP= a+ b5- a= 15 ( b-4 a )
Answer: (2)