Let ak=( k) i+ j and bk= i-( k) j, where k= 2k-1 2n+1, for some n N, n>5. Then the value of k=1n | ak |2 k=1n | bk |2 is
Answer
3
Solution
| ak |2= 2 k+1= 2 k, | bk |2=1+ 2 k=cosec2 k
2 +cosec2 = 1 2 2 = 4 2 2 =4 cosec2 2
2 k=4 cosec2 k+1-cosec2 k (as 2 k= k+1)
Let T= k=1ncosec2 k.
n+1= 2n 2n+1= - 1 cosec2 n+1=cosec2 1
k=1ncosec2 k+1= k=2n+1cosec2 k=T
k=1n 2 k=4T-T=3T
Required ratio = 3TT=3
Answer: 3