A solid cylinder of mass 2 kg and radius 4 cm is rotating about its axis at the rate of 3 rpm. The torque required to stop after 2 revolutions is :
- 2 10-3 N m
- 2 10-6 N m
- 2 106 N m
- 12 10-4 N m
Answer
(2) 2 10-6 N m
Solution
Moment of inertia: I = 12MR2 = 12 2 (0.04)2 = 1.6 10-3 kg m2
Initial angular speed: 0 = 3 rpm = 3 2 60 = 10 rad s-1
Angle turned: = 2 rev = 2 2 = 4 2 rad
Using 2 = 02 - 2 with = 0:
⇒ = 022 = 2/1008 2 = 1800 rad s-2
∴ = I = 1.6 10-3800 = 2 10-6 N m
Answer: (2)