A solid sphere is in rolling motion. In rolling motion a body possesses translational kinetic energy (Kt) as well as rotational kinetic energy (Kr) simultaneously. The ratio Kt : (Kt + Kr) for the sphere is
- 7 : 10
- 5 : 7
- 10 : 7
- 2 : 5
Answer
(2) 5 : 7
Solution
Kt = 12mv2
For a solid sphere, I = 25mR2 and = vR:
Kr = 12I 2 = 12 25mR2 v2R2 = 15mv2
Kt + Kr = 12mv2 + 15mv2 = 710mv2
Kt : (Kt + Kr) = 12 : 710 = 5 : 7
Answer: (2)