If the lattice parameter for a crystalline structure is 3.6 A, then the atomic radius in fcc crystal is
- 2.92 A
- 1.27 A
- 1.81 A
- 2.10 A
Answer
(2) 1.27 A
Solution
In an fcc unit cell, atoms touch along the face diagonal.
2 a = 4r
r = a2 2
= 3.62 1.414
= 1.27 A
Answer: (2)