AB crystallizes in a body centred cubic lattice with edge length 'a' equal to 387 pm. The distance between two oppositely charged ions in the lattice is
- 335 pm
- 250 pm
- 200 pm
- 300 pm
Answer
(1) 335 pm
Solution
In a bcc (CsCl-type) arrangement, the ion at the body centre touches the oppositely charged ions at the corners along the body diagonal.
2(r+ + r-) = 3 a
r+ + r- = 32 387
= 1.732 3872
= 335 pm
Answer: (1)