Structure of a mixed oxide is cubic close packed (ccp). The cubic unit cell of mixed oxide is composed of oxide ions. One fourth of the tetrahedral voids are occupied by divalent metal A and the octahedral voids are occupied by a monovalent metal B. The formula of the oxide is
- ABO2
- A2BO2
- A2B3O4
- AB2O2
Answer
(4) AB2O2
Solution
Number of oxide ions in a ccp unit cell = 4
⇒ Tetrahedral voids = 2 4 = 8 and octahedral voids = 4
A atoms = 14 8 = 2
B atoms = 4 (all octahedral voids)
⇒ A : B : O = 2 : 4 : 4 = 1 : 2 : 2
∴ Formula = AB2O2
Check: charge = 2(+2) + 4(+1) = +8 = 4 2, so the oxide is neutral.
Answer: (4)