Let a = - i + 2 j + 2 k, b = 8 i + 7 j - 3 k and c be a vector such that a c = b. If c ( i + j + k) = 4, then | a + c|2 is equal to :
- 30
- 33
- 27
- 35
Answer
(3) 27
Solution
a b = -8 + 14 - 6 = 0, so a c = b is consistent.
Take cross product of a with both sides: a ( a c) = a b
( a c) a - | a|2 c = a b
| a|2 = 1 + 4 + 4 = 9
a b = vmatrix i & j & k \ -1 & 2 & 2 \ 8 & 7 & -3 vmatrix = -20 i + 13 j - 23 k
Let a c = . Then 9 c = a + 20 i - 13 j + 23 k
9 c = (20 - ) i + (2 - 13) j + (2 + 23) k
c ( i + j + k) = 4 (20 - ) + (2 - 13) + (2 + 23) = 36
3 + 30 = 36 = 2
c = 18 i - 9 j + 27 k9 = 2 i - j + 3 k
a + c = i + j + 5 k
| a + c|2 = 1 + 1 + 25 = 27
Answer: (3)