A gas is allowed to expand in a well insulated container against a constant external pressure of 2.5 atm from an initial volume of 2.50 L to a final volume of 4.50 L. The change in internal energy U of the gas in joules will be
- -500 J
- -505 J
- +505 J
- 1136.25 J
Answer
(2) -505 J
Solution
Well insulated ⇒ adiabatic ⇒ q = 0
First law: U = q + w = w
w = -pex V = -2.5 atm (4.50 - 2.50) L
= -5.0 L atm
= -5.0 101 J = -505 J (1 L atm ≈ 101 J)
∴ U = -505 J
Answer: (2)