For the reaction, X2O4(l) 2XO2(g) = 2.1 kcal, S = 20 cal K-1 at 300 K Hence, is
- 2.7 kcal
- -2.7 kcal
- 9.3 kcal
- -9.3 kcal
Answer
(2) -2.7 kcal
Solution
g = 2 - 0 = 2
= + g RT
= 2.1 + 2 2 3001000
= 2.1 + 1.2 = 3.3 kcal (taking R 2 cal K-1 mol-1)
= - T
= 3.3 - 300 201000
= 3.3 - 6.0 = -2.7 kcal
Answer: (2)