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Let and be the roots of the equation p x2+q x-r=0, where p 0. If p, q and r be the consecutive terms of a non constant G.P. and 1 + 1 = 34, then the value of ( - )2 is :
(4) 809
Let q=pR, r=pR2 (G.P., R 1)
1 + 1 = + = -q/p-r/p= qr= 1R= 34 R= 43
( - )2=( + )2-4 = q2p2+ 4rp
=R2+4R2=5R2
=5 169= 809
Answer: (4)
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