For 0<c<b<a, let (a+b-2c)x2+(b+c-2a)x+(c+a-2b)=0 and 1 be one of its roots. Then, among the two statements
- only (II) is true
- Both (I) and (II) are true
- only (I) is true
- Neither (I) nor (II) is true
Answer
(2) Both (I) and (II) are true
Solution
Sum of coefficients =(a+b-2c)+(b+c-2a)+(c+a-2b)=0 ⇒ x=1 is a root
= c+a-2ba+b-2c (product of roots)
Here a+b-2c>0 since a, b>c
(I): <0 b> a+c2 (AM) > ac (GM) ⇒ (I) is true
(II): >0 b< a+c2; <1 3c<3b, i.e. b>c
∵ c< ac< a+c2 too, b may equal ac ⇒ (II) is true
Answer: (2)