Let a be the sum of all coefficients in the expansion of (1-2x+2x2 )2023 (3-4x2+2x3 )2024 and b= x 0 ( 0x (1+t)t2024+1dtx2 ). If the equations cx2+dx+e=0 and 2bx2+ax+4=0 have a common root, where c, d, e R, then d : c : e equals
- 2 : 1 : 4
- 1 : 1 : 4
- 1 : 2 : 4
- 4 : 1 : 4
Answer
(2) 1 : 1 : 4
Solution
Sum of coefficients: put x=1 ⇒ a=(1)2023(1)2024=1
b= x 0 (1+x) (x2024+1 ) 2x= 12 (L'Hôpital's rule)
⇒ second equation: x2+x+4=0, D=1-16<0 ⇒ roots are non-real
c, d, e are real, non-real roots occur in conjugate pairs ⇒ both roots are common
c1= d1= e4 ⇒ d : c : e=1 : 1 : 4
Answer: (2)