A series combination of n1 capacitors, each of value C1, is charged by a source of potential difference 4V. When another parallel combination of n2 capacitors, each of value C2, is charged by a source of potential difference V, it has the same (total) energy stored in it as the first combination has. The value of C2, in terms of C1, is then
- 2C1n1 n2
- 16 n2n1C1
- 2 n2n1C1
- 16C1n1 n2
Answer
(4) 16C1n1 n2
Solution
Series combination: Cs = C1n1
U1 = 12Cs(4V)2 = 12 C1n1 16V2
Parallel combination: Cp = n2C2
U2 = 12n2C2V2
U1 = U2
16C1n1 = n2C2
C2 = 16C1n1 n2
Answer: (4)