Standard electrode potential for the cell with cell reaction Zn(s) + Cu2+(aq) Zn2+(aq) + Cu(s) is 1.1 V. Calculate the standard Gibbs energy change for the cell reaction. (Given F = 96487 C mol-1)
- -200.27 J mol-1
- -200.27 kJ mol-1
- -212.27 kJ mol-1
- -212.27 J mol-1
Answer
(3) -212.27 kJ mol-1
Solution
r G = -nFE cell, with n = 2 (Zn Zn2+ + 2e-)
rG = -2 96487 1.1
= -212271 J mol-1
= -212.27 kJ mol-1
Answer: (3)