For a cell involving one electron E cell = 0.59 V at 298 K, the equilibrium constant for the cell reaction is : [Given that 2.303 RTF = 0.059 V at T = 298 K]
- 1.0 1030
- 1.0 1010
- 1.0 102
- 1.0 105
Answer
(2) 1.0 1010
Solution
As per NCERT, at equilibrium Ecell = 0, so the Nernst equation gives
E cell = 2.303 RTnF Kc = 0.059n Kc
Kc = n E cell0.059
= 1 0.590.059
= 10
Kc = 1.0 1010
Answer: (2)