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The pressure of H2 required to make the potential of H2-electrode zero in pure water at 298 K is
(3) 10-14 atm
Electrode reaction: 2H+(aq) + 2e- H2(g), E = 0
Nernst equation:
E = E - 0.0592 pH2[H+]2
In pure water [H+] = 10-7 M.
For E = 0: pH2[H+]2 = 0
pH2 = [H+]2 = (10-7)2 = 10-14 atm
Answer: (3)
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