Two bodies of mass 1 kg and 3 kg have position vectors i + 2 j + k and -3 i - 2 j + k, respectively. The centre of mass of this system has a position vector :
- -2 i - j + k
- 2 i - j - 2 k
- - i + j + k
- -2 i + 2 k
Answer
(1) -2 i - j + k
Solution
rcm = m1 r1 + m2 r2m1 + m2
rcm = 1( i + 2 j + k) + 3(-3 i - 2 j + k)1 + 3
rcm = -8 i - 4 j + 4 k4
rcm = -2 i - j + k
Answer: (1)