The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is (charge on electron = 1.60 10-19 C)
- 6 1023
- 6 1020
- 3.75 1020
- 7.48 1023
Answer
(3) 3.75 1020
Solution
Q = It = 1 60 = 60 C
Number of electrons = Qe = 601.60 10-19
= 3.75 1020
Answer: (3)