For the reaction A(g) 2B(g), the backward reaction rate constant is higher than the forward reaction rate constant by a factor of 2500, at 1000 K. [Given : R = 0.0831 L atm mol-1 K-1] Kp for the reaction at 1000 K is
- 0.033
- 0.021
- 83.1
- 2.077 105
Answer
(1) 0.033
Solution
At equilibrium, Kc = kfkb
∵ kb = 2500 kf ⇒ Kc = 12500 = 4 10-4
ng = 2 - 1 = 1
Kp = Kc(RT) ng
= 4 10-4 (0.0831 1000)1
= 4 10-4 83.1
= 0.0332 0.033
Answer: (1)