Bond order of 1.5 is shown by
- O2+
- O2-
- O22-
- O2
Answer
(2) O2-
Solution
Bond order = 12(Nb - Na)
O2 (16 electrons): Nb = 10, Na = 6 ⇒ bond order = 12(10 - 6) = 2
O2+ (15 electrons): bond order = 12(10 - 5) = 2.5
O2- (17 electrons): bond order = 12(10 - 7) = 1.5
O22- (18 electrons): bond order = 12(10 - 8) = 1
∴ Bond order of 1.5 is shown by O2-.
Answer: (2)