When glycerol is treated with excess of HI, it produces
- 2-iodopropane
- allyl iodide
- propene
- glycerol triiodide
Answer
(1) 2-iodopropane
Solution
CH2OH-CHOH-CH2OH HI CH2=CH-CH2I (allyl iodide)
CH2=CH-CH2I HI CH3-CHI-CH2I
CH3-CHI-CH2I CH3-CH=CH2 + I2
CH3-CH=CH2 HI CH3-CHI-CH3 (Markovnikov addition)
∴ With excess HI the final product is 2-iodopropane.
Answer: (1)