Consider the following reaction : Ethanol PBr3 X alc. KOH Y [(ii) H2O, heat](i) H2SO4, room temperature Z the product Z is
- CH3CH2-O-CH2-CH3
- CH3-CH2-O-SO3H
- CH3CH2OH
- CH2=CH2
Answer
(3) CH3CH2OH
Solution
CH3CH2OH PBr3 CH3CH2Br X = bromoethane
CH3CH2Br alc. KOH CH2=CH2 (dehydrohalogenation) Y = ethene
Cold conc. H2SO4 adds to ethene: CH2=CH2 + H2SO4 CH3CH2OSO3H
On heating with water it is hydrolysed: CH3CH2OSO3H + H2O CH3CH2OH + H2SO4
As per NCERT, this is acid-catalysed hydration of an alkene Z = ethanol
Answer: (3)