For a given exothermic reaction, Kp and K'p are the equilibrium constants at temperatures T1 and T2, respectively. Assuming that heat of reaction is constant in temperature range between T1 and T2, it is readily observed that
- Kp > K'p
- Kp < K'p
- Kp = K'p
- Kp = 1K'p
Answer
(1) Kp > K'p
Solution
van't Hoff equation:
K'pKp = H 2.303 R ( T2 - T1T1T2 )
For an exothermic reaction H < 0; with T2 > T1 the right-hand side is negative.
⇒ K'p < Kp, i.e. the equilibrium constant of an exothermic reaction decreases with rise in temperature.
∴ Kp > K'p
Answer: (1)